enthalpy change of any displacement reaction essay

1 ) Experiment Quantity: 4 2 . Date: 15/10/07 3. Title: Enthalpy alter of a displacement reaction 4. Aims/Objective: To determine the enthalpy transform of a displacement reaction (Between zinc and copper (II) ions) five. Introduction: Surplus zinc powdered is added in a assessed amount of aqueous copper mineral (II) sulphate. The temperatures change is then measured during time therefore the enthalpy of this reaction could be calculated. 6th. Relevant Equations/Chemical Reactions Engaged: Zn (s) + CuSO4(aq)? ZnSO4(aq) + Cu(s) 7. Chemicals: 1 . 00M water piping (II) sulphate solution twenty-five.

0 cm3 Zinc natural powder (in excess) 5. 9g.

8. Equipment and gear: Safety stage show x one particular Spatula x 1 twenty-five cm3 pipette x one particular Balance back button 1 Pipette filler by 1 Thermometer(0-100 oC) times 1 Polystyrene cup with lid times 1 Digital timer back button 1 Weighting bottle back button 1 9. Procedure: 1 . An empty polystyrene cup was weighted. installment payments on your 5. 9g of zinc powder (in excess)was weighted and then added into the polystyrene cup. three or more. The temp of the copper (II) sulphate solution in beaker was recorded every half minute intended for 2 . 5 minutes and then 25. 0 cm3 of the water piping (II) sulphate solution was pipetted right into a polystyrene glass.

4. Thermometer was put through the opening of the sport bike helmet.

The solution was stirred continually and the temperature was recorded every single half tiny for 6 minutes. 10. Observation: The blue coloring of the answer disappears. Brownish solid is created. Some zinc powder continues to be there. eleven. Data, Calculation and Effects: a. Effects Table Time/min 0. zero 0. 5 1 . zero 1 . five 2 . 0 2 . five 3. zero 3. five 4. zero 4. five Temperature/oC twenty-five. 0 25. 0 twenty-five. 0 25. 0 twenty-five. 0 25. 0 25. 0 60. 0 73. 0 71. 0 Time/min 5. 0 5. your five 6. 0 6. 5 7. zero 7. 5 8. 0 8. 5 9. zero 9. 5 Temperature/oC 69. 0 sixty-eight. 0 67. 0 66. 5 sixty four. 5 63. 5 62. 5 61. 5 60 59 b. Calculations 1&2. Graph of temperature against time.

a few. Energy modify of remedy = twenty-five x 10-3 x some. 18 back button (76. five ” 25) = a few. 38175 kJ mol-1 Strength change from the cup sama dengan 2 . 27 x 10-3 x 1 . 3 x (76. 5- 25) sama dengan 0. 1519765 kJ mol-1 Enthalpy modify for the quantities used = ” (5. 38175 + zero. 1519765) = ” your five. 5337265 kJ mol-1 Assumptions: (1) The specific heat potential of the option is the same as those of water. (2) Heat can be not lost to the encircling. 4. No . of mole of CuSO4 = 1 x 25 x 10-3 = 0. 025 mol Required enthalpy change sama dengan ” [(5. 5337265)/0. 025] = ” 221 kJ mol-1 Zn (s) + CuSO4(aq)? ZnSO4(aq) + Cu(s)? H sama dengan ” 221 kJ mol-1 12. Conclusion:

It was found that the enthalpy change of any displacement reaction (Between zinc and copper (II) ions) was ” 221 kJ mol-1. 13. Answer to concerns 1 . % error = [- 221 ” (- 217)]/- 217 back button 100% sama dengan 1 . 84% The experimental value is far more negative compared to the accepted value. 2 . Factors: (1) Warmth is misplaced to the encircling. (2) The actual heat capacity of the remedy is not the same as that of drinking water. 3. CuSO4 is not really in excess which is often used up totally. No matter more zinc can be used or dust is very finely divided, equivalent the solution can be used so there is certainly same increase in temperature.

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